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在模拟抛物线槽式太阳能集热器的接收管内的传热时,需要给出如下图所示的热通量(周向变化)。在壁面边界上指定的方法如下。

1.提取出各个角度下的X、Y坐标
X=R*Cosϴ;Y=R*Sinϴ,其中R是管半径。Z坐标间隔填写,为了跨越整个管长。因此,可以创建分布文件数据。如下所示定义分布文件格式,采用.CSV格式。
| [Name] | |||
| wall-solid | |||
| [Data] | |||
| x | y | z | heat-flux |
| 0.0125 | 0 | 0 | 0 |
| 0.00625 | 0.010825 | 0 | 0 |
| 7.66E-19 | 0.0125 | 0 | 0 |
| -0.00625 | 0.010825 | 0 | 50000 |
| -0.0125 | 1.53E-18 | 0 | 30000 |
| -0.00625 | -0.01083 | 0 | 50000 |
| -2.30E-18 | -0.0125 | 0 | 0 |
| 0.00625 | -0.01083 | 0 | 0 |
| 0.0125 | 0 | 0.25 | 0 |
| 0.00625 | 0.010825 | 0.25 | 0 |
| 7.66E-19 | 0.0125 | 0.25 | 0 |
| -0.00625 | 0.010825 | 0.25 | 50000 |
| -0.0125 | 1.53E-18 | 0.25 | 30000 |
| -0.00625 | -0.01083 | 0.25 | 50000 |
| -2.30E-18 | -0.0125 | 0.25 | 0 |
| 0.00625 | -0.01083 | 0.25 | 0 |
| 0.0125 | 0 | 0.5 | 0 |
| 0.00625 | 0.010825 | 0.5 | 0 |
| 7.66E-19 | 0.0125 | 0.5 | 0 |
| -0.00625 | 0.010825 | 0.5 | 50000 |
| -0.0125 | 1.53E-18 | 0.5 | 30000 |
| -0.00625 | -0.01083 | 0.5 | 50000 |
| -2.30E-18 | -0.0125 | 0.5 | 0 |
| 0.00625 | -0.01083 | 0.5 | 0 |
| 0.0125 | 0 | 0.75 | 0 |
| 0.00625 | 0.010825 | 0.75 | 0 |
| 7.66E-19 | 0.0125 | 0.75 | 0 |
| -0.00625 | 0.010825 | 0.75 | 50000 |
| -0.0125 | 1.53E-18 | 0.75 | 30000 |
| -0.00625 | -0.01083 | 0.75 | 50000 |
| -2.30E-18 | -0.0125 | 0.75 | 0 |
| 0.00625 | -0.01083 | 0.75 | 0 |
| 0.0125 | 0 | 1 | 0 |
| 0.00625 | 0.010825 | 1 | 0 |
| 7.66E-19 | 0.0125 | 1 | 0 |
| -0.00625 | 0.010825 | 1 | 50000 |
| -0.0125 | 1.53E-18 | 1 | 30000 |
| -0.00625 | -0.01083 | 1 | 50000 |
| -2.30E-18 | -0.0125 | 1 | 0 |
| 0.00625 | -0.01083 | 1 | 0 |


2.加载到壁面边界

3.所应用的热通量分布如下图所示。
